1. The force of attraction between two bodies at a
certain separation is 10 N. What will be the force
of attraction between them if the separation is
reduced to half ? Ans.40N
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force of attraction is always inversely proportional to square of distance.
so F1/F2=(d2/d1)^2
10/F2=(1/2)^2
F2=40N
hope this helps you out.
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