Question

1. The LCM of two numbers is 45 and their HCF is 5. How many such pairs of numbers
are possible?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

As both the numbers have the highest common factor 12 it clearly means that the both the numbers are the multiples if 12

So let the numbers be 12x and 12y

As given their sum is 84

according to the question :12x+12y=84

12 (x+y)=84

x+y=7

So the number of pairs with 7 as their sum are (1,6),(2,5),(3,4)

That is three pairs

So the numbers are (12,72),(24,60), (36,48)

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