Question

1. THE LEAST ANGLE OF DEVIATION OF A GLASS PRISM IS EQUAL TO ITS REFRACTING ANGLE.THE REFRACTIVE INDEX OF GLASS IS 1.5.THEN THE ANGLE OF PRISM IS?

2.THE ANGLE OF MINIMUM DEVIATION FOR A 75 DEGREE PRISM OF DENSE GLASS IS FOUND TO BE 45 DEGREE WHEN IN AIR AND 15 DEGREE WHEN IMMERSED IN LIQUID.THE REFRACTIVE INDEX OF THE LIQUID IS?

Answer 1

The angle of prism is A = cos^−1(3/4) and the refractive index of the liquid is 0.816

Explanation:

We know

μ12= sin A+D / 2 ÷ sin A / 2

Here A = D

1.5 = sinA ÷ sin A/2 =2 cosA/2

A = cos^−1(3/4)

Question 2:

μ(air) / μ(liquid) = sin A+D(air) /2 ÷ sin A + D (liq) /2

1 / μliq = sin(60) / sin(45) = 1.22

μ (liq) = 0.816  Refractive index of the liquid.

Thus the angle of prism is A = cos^−1(3/4) and the refractive index of the liquid is 0.816

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