1. The length of the rectangular field is thrice its
breadth. Its perimeter is 400 m. Find its length and
breadth.
(a) L = 150m, b=50m (b) L = 100m, b=20m
(c) L=20m, b=150m (d)L=150cm,b=50cm
2. Find the value of x, in the given equation
0.6x + 0.8 = 0.56x + 2.32.
(a) x=38 (b) x=36
(c) x= 40 (d) x= 0
3. Ramu’s mother is 49 years old. She is 4 years older
than three times Ramu’s age. What is Ramu’s age?
(a) 45 years (b) 15 years
(c) 4 years (d) 40 years
Answers
Answer:
1. option A
2.option B
3. option A
Step-by-step explanation:
present age of Ramu = 49-4= 45
hope this would help you
Answer:
Question 1
Let the breadth be x and length be 3x ( Given length is 3 times the breadth)
we know the perimeter of a rectangle is:
2(l+b)
Given perimeter is 400,
therefore, 2(l+b) = 400
therefore, 2(l+b) = 4002(3x+x) = 400
therefore, 2(l+b) = 4002(3x+x) = 4008x = 400
x = 50, thus breadth is 50
therefore length is 3x i.e. 3*50 = 150
Hence, length = 150, breadth = 50
Option a. is correct
Question 2
0.6x + 0.8 = 0.56x + 2.32
Taking the variables on one side
0.6x - 0.56x = 2.32 - 0.80
0.04x = 1.52
x = 38
Option a. is correct
Question 3
Let Ramu's age be x,
According to the question,
His mother's age is 3x + 4 = 49
therefore, 3x + 4 = 49
3x = 45
x = 15
Option b. is correct