Question

1. The maximum amount of Baso, that can be obtained on moxing 0.5 mol BaCl, with 1 mol H,SO, IS BaCl2 + H SO BaSO. + 2HCI (a) 0.5 mol (b) 0.1 mol (c) 0.15 mol (d) 0.2 mol 2. ​

Answer 1

$\huge\frak{Answer}$

BaCl 2+H 2SO 4

→BaSO 4 +2HCl

1 mol of BaCl 2 reacts with 1 mol H 2 SO 4 to give 1 mol of BaSO 4 .

Here , BaCl 2 is the limiting reagent.

Therefore, moles of BaSO 4 formed = moles of BaCl 2 present = 0.5mol.

Answer 2

Answer:

0.2 mol 2.

Step-by-step explanation:

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