Question

1. The motion of a particle is described by
x = xo(1 - {e}^{ - kt} ) \: where \: t \geqslant 0 \: \: \: \: \: \: \: \: xo > 0 \: \: \: \: \: \: \: \: \: k > 0x=xo(1−e−kt)wheret⩾0xo>0k>0
With what
velocity does the particle start?
\begin{gathered}(a) \frac{xo}{k} \\ (b) xok\\( c) \frac{k}{xo} \\ ( d)2xok\end{gathered}(a)kxo​(b)xok(c)xok​(d)2xok​

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Answer 1

Explanation:

bzbzbzbzbzbxbbxbxhxhxhxhxhxhhxbxhxhxhxhxhxhxhxhhxjxhxhxhxhxjxhxh

its zero