Question

1.
The number of electrons in oxygen atom in
0.3 g-molecule of Mohr's salt
[FeSO4(NH4)2SO4.6H2O] is
(1) 4.2 NA
(2) 42 NA
(3) 25.2 NA
(4) 33.6 Na​

Answer 1

Answer:

ans si 1:

Explanation:

[FeSo4(NH4)2so4.6H2o]is :

4.2NA

Answer 2

Answer:

4) 33.6

Explanation:

Total O2 atoms in salt = 14

Thus, total electrons = 14×NA×6

=33.6NA

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