Question

1
The particular value of
1/D3sinx is
​

Answer 1

Answer:

envy you are my bfungist friend is teaching

Answer 2

Answer:

-3cos(x)

Step-by-step explanation:

1/D $\equiv$ $\int$

P.I of $\frac{1}{D} [3sinx]$ is given  by $3\int\limits \, sinxdx =-3 cos(x).$

problem can be also solved by transforming sinx =$\frac{e^{ix}-e^{-ix}}{2i}$.