Question

1.The perimeter of a parallelogram is 150one of its sides is greater than the other by 25. Find the lengths of all the sides of the parallelogram​

Answer 1

Answer:

opposite sides are equal in a parallelogram

let two sides be x

so, other two sides are x+25

sum of sides=perimeter

ATQ

x+x+x+25+x+25=150

4x+50=150

4x=150-50=100

×=100/4

x=25

x+25=25+25=50

so the sides are 25,25,50,50

Answer 2

let breadth of llgm=x
then, length of llgm=x+25
perimeter of llgm=2(l+b)
150=2(x+x+25)
150=2(2x+25)
150=4x+50
4x=100
x=20
breadth of llgm=20
length=20+25
=45