(1) The perimeter of a rectangle is 200 cm. Its length is three times its breadth. Find it
length and breadth.
Answers
Answer:
Answer:
Length = 75cm.
Breadth = 25cm.
Given:
The perimeter of a rectangle is 200 cm.
Its length is three times its breadth.
To find:
Find it's length and breadth.
Solution:
Given that,
Its length is three times its breadth.
Let us assume length as l
And, Let us assume breadth as b
So,
It can be written as l = 3b
We know that,
Perimeter of a rectangle = 2(l + b)
Now,
l × b = 200
Given, Perimeter = 200.
We know that, l = 3b..
By replacing 3b in place of l, We get :
➨ 2(3b + b) = 200
➨ 6b + 2b = 200
➨ 8b = 200
➨ b = \bf \dfrac{200}{8}8200
➨ b = 25cm.
Hence,
Breadth = 25cm.
Length = 3b = 3 × 25 = 75cm.
Verification:
2(3b + b) = 200
➨ 2(3(25) + 25) = 200
➨ 2( 75 + 25 ) = 200
➨ 2( 100 ) = 200
➨ 200 = 200
LHS = RHS
Hence , Verified.
Answer:
Length = 75cm.
Breadth = 25cm.
Given:
The perimeter of a rectangle is 200 cm.
Its length is three times its breadth.
To find:
Find it's length and breadth.
Solution:
Given that,
Its length is three times its breadth.
Let us assume length as l
And, Let us assume breadth as b
So,
It can be written as l = 3b
We know that,
Perimeter of a rectangle = 2(l + b)
Now,
l × b = 200
Given, Perimeter = 200.
We know that, l = 3b..
By replacing 3b in place of l, We get :
➨ 2(3b + b) = 200
➨ 6b + 2b = 200
➨ 8b = 200
➨ b = \bf \dfrac{200}{8}8200
➨ b = 25cm.
Hence,
Breadth = 25cm.
Length = 3b = 3 × 25 = 75cm.
Verification:
2(3b + b) = 200
➨ 2(3(25) + 25) = 200
➨ 2( 75 + 25 ) = 200
➨ 2( 100 ) = 200
➨ 200 = 200
LHS = RHS
Hence , Verified.