Question

1. The perpendicular distance of a point P (3, 4) from the y-axis is​

Answer 1

Answer:

Step-by-step explanation:

Perpendicular distance of the point p ( 3 4) from the y-axis is equal to its x coordinate.

Therefore it is 3 units

Regards...................

Answer 2

Given point is P(3,4) and we are asked to find the perpendicular distance from y-axis.

Since it asked for perpendicular then it is parallel to x-axis. i.e, ordinate will be same.

Therefore, Second point will be M(0,4)

Now , We have both the points:

Points:

• $P(x_{1}, y_{1}) = (3,4)$
• $M(x_{2}, y_{2}) = (0,4)$

By Distance Formula, we get:

$\quad \; \qquad \boxed{\because \quad D = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2} }</p><p>\\ \Rightarrow \qquad PM = \sqrt{(0 - 3)^2+(4-4)^2} \\ \Rightarrow \qquad PM = \sqrt{(-3)^2 + (0)^2} \\ \Rightarrow \qquad PM = \sqrt{9} \\ \quad \qquad \; \boxed{PM = 3}$

ANSWER: 3 UNITS