Question

1. The present age of father is four times the age of his son. After 10 years, age of father willbecome three times the age of his son. Find their present ages. ​

Answer 1

Step-by-step explanation:

Let age of son = x

Then age of father = 5x - 3

After 5 years age of son = x + 5

Then after 5 age of father

= 3(x + 5) + 3

So, according to the given condition

5x - 3 + 5 = 3(x + 5) + 3

5x + 2 = 3x + 15 +3

2x = 18 - 2

2x = 16

x = 16/2 = 8

Therefore age of son = 8 years

Answer 2

Answer:

let age of father be x and son be y

Step-by-step explanation:

now ATQ

x=4y. case 1

x+10 = 3(y+10). case 2

x+10 = 3y+ 30

x - 3y = 20

now putting value of x.

4y-3y=20

y= 20

son age =20

father age=80