Question

1. The present
resent ages of A and B are in the ratio 7:5. Ten years later, their ages will
the ratio 9:7. Find their present ages.
be in the ratio ,find the present age​

Answer 1

Step-by-step explanation:

a.t.q= according to question

"= same as written above

Answer 2

Appropriate Question:

The present ages of A and B are in ratio 7:5. Ten years later, their ages will be in ratio 9:7. Find their present ages.

Answer:

$\bigstar\fbox\purple{\sf A's\:age = 35\:years}$

$\bigstar\fbox\purple{\sf B's\:age = 25\:years}$

Step-by-step explanation:

★ Given,

• Present age of A and B are in ratio 7:5.
• Ten years later, their ages will be in ratio 9:7.

★ To Find,

• Their present ages = ?

★ Solution,

☞ Let the present age of A be 7x and B be 5x.

⚩ After 10 years :

☞ Present age of A = (7x + 10)

☞ Present age of B = (5x + 10)

⚩ According to the question :

:$\implies\sf\red{\dfrac{7x + 10}{5x + 10} = \dfrac{9}{7}}$

:$\implies\textsf{7(7x + 10) = 9(5x + 10)}$

:$\implies\textsf{49x + 70 = 45x + 90}$

:$\implies\textsf{49x - 45x = 90 - 70}$

:$\implies\textsf{4x = 20}$

:$\implies\sf{x = \cancel{\dfrac{20}{4}}}$

:$\implies\fbox\purple{\sf x = 5}$

⚩ Putting the value of x :

☞ Age of A = 7x = 7(5) = 35 years

☞ Age of B = 5x = 5(5) = 25 years

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