Question

1. The pressure of air ar a certain place is 76 cm of mercury Calculate the pressure in Si units.
Density of mercury = 13600 kg mand g = 9.8 ms?​

Answer 1

Explanation:

Accordingtoquestion:

Pressure=hpg∣h=76cm=0.76m

⇒P=13.6×10

3

kg/m

3

,g=10m/s

2

so,

⇒P=0.76×3.6×10

3

×10

∴1.03×10

5 pa

Answer 2

Given :-

Height of the mercury column = 76 cm

Density of mercury = 13600 kg

To Find :-

The pressure of the mercury in SI units.

Analysis :-

Here we are given with the height and density of the mercury.

In order to find the pressure substitute the given values in the question such that pressure is equal to height into density into gravity and find the pressure of the air accordingly.

Solution :-

We know that,

• ρ = Density
• h = Height
• p = Pressure
• g = Gravity

Using the formula,

$\underline{\boxed{\sf Pressure=Height \times Density \times Gravity }}$

Given that,

Height (h) = 76 cm = 0.76 m

Density (ρ) = 13600 kg

Gravity (g) = 9.8 m/s

Substituting their values,

⇒ p = hρg

⇒ p = 0.76 × 13600 × 9.8

⇒ p = 101292.8 Nm²

Therefore, the pressure in SI units is 101292.8 Nm².