Question

1) The product of 3x’ and -5xy is _
2} The product of (x+y) (x-y) (x++y?) is _
3) What will be the remainder when 3x-2x+1 is divided by x+5?
4) What must be added to y - y-3y - 2 to get y?-5y+67
5) When (3y+1)(27-3)=6y +ay-3, what will be the value of (a)?
6) If x=3, y=2, then (x-7)(x*+xy+y?) is
7) Subtract 72pq-309?-15p?from 30p +40q-12pq ?
8) The sides of a triangle are 3x+1, 4x+2 and 5x. Find the perimeter of the triangle.
9) The length and breadth of a rectangle are (3a-4b) cms and (5b+2a) cms. Find it area and perimeter.
10) Using the identities evaluate the following
a) (102)2 b) (311) C) (89) d) 13x7 e) 125 x 11.5 f) 153 x 147
11) Expand 1526.26 using exponents.
12) Find 'a' such that (-5)**2 x (+5)* = (-5)
13) Find the value of n in the given expression: 22/1-11 x 22n = 2+1
14) Simplify (-2X(-3)*x (4) and write the answer in exponential form.
15) Find the value of (4-4x2) x 34
16) Write the numbers in expanded forms:
a) 20058 (b) 423719
(c) 680071
(d) 5004132
17) What should (-)- be divided so that the quotient becomes 97
18) What should
be multiplied so that product becomes 25?
19) Find the product of the cube of (-2/3) and the square of (4/-5).
20) Simplify and express with positive exponents.
al (4/5)*x (6)
b) c(-3) X (-1/97%​

Answer 1

Answer:

In an algebraic expression, if the powers of the variables are whole numbers then the algebraic expression is a polynomial.

(i)

y+

1

y

=y+y-1

Here, one of the powers of y is −1, which is not a whole number. So, y +

1

y

is not a polynomial.

(ii)

2 - 5

√

x

=2-5x

1

2

Here, the power of x is

1

2

, which is not a whole number. So, 2 - 5

√

x

is not a polynomial.

(iii)

x2 + 7x + 9

Here, the powers of the variable x are 2, 1 and 0, which are whole numbers. So, x2 + 7x + 9 is a polynomial.

(iv)

2m-2 + 7m - 5

Here, one of the powers of m is −2, which is not a whole number. So, 2m-2 + 7m - 5 is not a polynomial.

(v)

10 = 10 × 1 = 10x0

Here, the power of x is 0, which is a whole numbers. So, 10 is a polynomial (or constant polynomial).