Question

1. The range of the data 14, 27, 29, 61, 45, 15, 9, 18, is
(a) 61 (b) 52 (c) 47 (d) 53
2. The class mark of the class 120-150 is
(a) 120 (b) 130 (c) 135 (d) 150
3. The class mark of a class is 10 and its class width is 6. The lower limit of the class is
(a) 5 (b) 7 (c) 8 (d) 10
4. In a frequency distribution, the class-width is 4 and the lower limit of first class is 10. If there are
six classes, the upper limit of last class is
(a) 22 (b) 26 (c) 30 (d) 34

Answer 1

q1 a 61

q2 b 130

q3 c 8

q4 c 30

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

1. The range of the data 14, 27, 29, 61, 45, 15, 9, 18, is

(a) 61

(b) 52

(c) 47

(d) 53

2. The class mark of the class 120 - 150 is

(a) 120

(b) 130

(c) 135

(d) 150

3. The class mark of a class is 10 and its class width is 6. The lower limit of the class is

(a) 5

(b) 7

(c) 8

(d) 10

4. In a frequency distribution, the class-width is 4 and the lower limit of first class is 10. If there are six classes, the upper limit of last class is

(a) 22

(b) 26

(c) 30

(d) 34

EVALUATION

1. Here the given set of observations are

14, 27, 29, 61, 45, 15, 9, 18

Highest value = 61

Lowest value = 9

Hence the required range of the data

= Highest value - Lowest value

= 61 - 9

= 52

The correct option is (b) 52

2. The given class is 120 - 150

Upper limit of the class = 150

Lower limit of the class = 120

Hence the required class mark of the class 120 - 150 is

$\displaystyle \sf{ = \frac{120 + 150}{2} }$

$\displaystyle \sf{ = \frac{270}{2} }$

$\displaystyle \sf{ = 135}$

The correct option is (c) 135

3. The class mark of a class = 10

The class width = 6

The lower limit of the class

$\displaystyle \sf{ = 10 - \frac{6}{2} }$

$\displaystyle \sf{ = 10 - 3}$

$\displaystyle \sf{ = 7 }$

The correct option is (b) 7

4. In a frequency distribution, the class-width is 4

The lower limit of first class = 10.

There are six classes

The six classes are 10 - 14 , 14 - 18 , 18 - 22 , 22 - 26 , 26 - 30 , 30 - 34

The upper limit of last class

= The upper limit of 6th class

= 34

The correct option is (d) 34

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