Math, asked by prasadbhagyawant944, 10 months ago


1) The ratio of corresponding sides of similar triangles is 3:5 then find the ratio of their areas.
A​

Answers

Answered by violetzimiya
2

Step-by-step explanation:

similar triangles is 3:5.

Step-by-step explanation:

Since there is no information about the type of similar triangles, so we can consider any two types of similar triangles.

Let’ s consider two right-angled triangles “∆CBA” and “∆PQR” where

CB & PQ be the perpendicular heights

AB & QR be the base

CA & PR be the hypotenuse

It is given that,

∆CBA ~ ∆PQR

The ratio of two sides of similar triangles = 3:5

i.e., BA:QR = 3:5 ….. (i)

Now, we know that if two triangles are given to be similar triangles then their corresponding sides are proportional to each other.

Therefore, we have

\frac{CB}{PQ} = \frac{BA}{QR}

PQ

CB

=

QR

BA

Substituting from (i)

⇒ \frac{CB}{PQ} = \frac{3}{5}

PQ

CB

=

5

3

Thus, the ratio of the height of the similar triangles is 3:5.

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