Question

1. The ratio of the length to the perimeter of a rectangle
is 3:8. Find its dimensions, given that its perimeter is
32 m. Also, find its area.​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

1st let's find out the length

so, ratio is 3:8 length and perimeter respectively.

if perimeter is 32m

then, 8=32

3=?

if we cross multiply we get

3×32/8

=96/8

length =12m

let's find breadth now

we have perimeter and length 32m and 12m respectively,

perimeter =2( l+b)

32=2( 12+ b)

32=24+2b

32-24=2b

8=2b

b=8/2

b=4m

now we got length and breadth

that is 12m and 4m respectively,

let's find area

area of rectangle =l×b

=12×4

=48m²

Answer 2

Answer :-

• Length of Rectangle = 12 cm.

• Breadth of Rectangle = 4 cm.

• Area of Rectangle = 48 sq.cm.

Explanation :-

Given :

• The ratio of the length to the perimeter of a rectangle is 3:8.

• Perimeter of Rectangle is 32 m.

To Find :

• Dimensions and Area of Rectangle.

Solution :

Let the length be 3x and the Perimeter be 8x.

It is Given that,

8x = 32 cm.

➞ x = 32 ÷ 8.

➞ x = 4 cm.

So, Length of Rectangle = 3x = 12 cm.

For Calculating Area, Let's find out the breadth too.

We know that,

Perimeter of Rectangle = 2(l + b).

➞ 2(12 + b) = 32 cm.

➞ 24 + 2b = 32 cm.

➞ 2b = 32 - 24.

➞ 2b = 8.

➞ b = 8 ÷ 2.

➞ b = 4 cm.

Now, Let's Calculate Area.

Area of Rectangle = l × b.

➞ Area = 12 × 4.

➞ Area = 48 sq.cm.

Therefore, Area of Rectangle = 48 sq.cm.