Question

1. The sides AB and AC of triangle ABC are congruent. BP and BQ are drawn from B to make congruent angles with BC and meet AC in points P and Q respectively. prove that:AB^2/AQ^2=AP/AQ​

Answer 1

Answer:

in ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh is

Step-by-step explanation:

in ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh isin ∆ abc /_bac = 90° from the mid point d of bc two lines parallel to ac and ab are drawn which intersect ab and ac at g and h if ab = 15 cm and ac= 8 cm then the length of the gh is