Question

1)The sum of numerator and denominator of a fraction is one more than four times the numerator. If the numerator is increased by 1 and the denominator is decreased by 1 then the denominator becomes twice the numerator. find the fraction.​

Answer 1

Step-by-step explanation:

Let the fraction =

y/x

First condition :

⇒x+y=2y−3

⇒x−y=−3

Second condition :

⇒

y−1{x−1

=

2

1

⇒2x−2=y−1

⇒2x−y=1

Subtract two equations ;

⇒2x−x=1+3⇒x=4

substitute in above equation

⇒y=1+8⇒y=7

∴ the fraction =

7/4

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Answer 2

Answer:

let x is numerator

let y is denominator

then, x+y = 4x + 1

3x-y = -1 -(1)

2(x+1) = y-1

2x+2= y-1

2x-y = -3 -(2)

Substracting 2 from 1

3x - y = -1

2x -y = -3

x = 2

then, y = 7

fraction =

x/y = 2/7

checking x+ y = 4x + 1

2+7 = 9

4x2 +1 = 9