Question

1. The sum of the digits of a two-digit number is 11. The digit at one's place is 2 more than twice the digit at ten's
place. Find the number,
2. The sum of three consecutive multiples of 5 is 60. Find the numbers.​

Answer 1

Answer:

1.Let the digits be x and y and the number be 10x+y

Then x+y =11, and

y=2x+2

Substituting the value of y =2x+2,we get

x+2x+2=11

or, 3x=9

x=9/3=3 and

y=2×3+2

=6+2

=8

Step-by-step explanation:

2.x+x+5+x+10=60

3x+15=60

3x=60

x=45/3

x=15

Answer 2

Answer:

1) the no. is 38

2) x = 15

Step-by-step explanation:

1) tens ones

x * 10 y*1

10x + y = 11

10x = 11-y

x = (11-y)/10 — eq.1

2×10x + 2 = y

20x = y-2

x = (y - 2)/ 20 — eq.2

from 1 and 2

(11-y)/10 = (y-2)/20

22 - 2y = y- 2

3y = 24

y = 8

put the value of y in eq. 1

x = 0.3, y = 8

The no. = 0.3*10 8*1 = 38

2) x + ( x + 5 ) + ( x + 10) = 60

3x + 15 = 60

3x = 45

x = 15