1. The sum of the digits of a two-digit number is 17.
The ten's digit of the number is 1 more than the
unit's digit. Find the two-digit number.
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Well
Let us consider unit's place be x
Then tens place would be (x+1)
Then
According to question
(x+1)+x=17
2x+1=17
2x=16
x=8
So digit at unit's place is 8
Another digit will be 8+1=9
So the number is 98
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