Question

1. The sum of three consecutive multiples of 8 is 888. Find the multiples​

Answer 1

Answer:

Let the first multiple of 8 be 8x. Also the third consecutive multiple of 8 will be 8(x+2). => x = 36. If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

Hope it helps you

Answer 2

let the first multiple be 8x

let the second multiple be 8 (x+1)

let the third multiple be 8 (x+2)

By A.T.Q

8x+ 8 (x+1)+ 8 (x+2) = 888

8x + 8x + 8 + 8x + 16 = 888

24x + 24 = 888

24x = 888-24

24x = 864

x = 864/24

x = 36

the multiple of first 8x = 8×36= 288

the multiple of second 8 (x+1)

=8(36+1)

= 8×37

= 296

the multiple of third 8 (x+2)

= 8 (36+2)

. = 8×38

= 304

total multiple = 288+296+304

= 888