1. The surface area of a sphere of radius 5 cm is five times the area of the curved surface of a cone of radius 4 cm. Find the height and the volume of the cone.
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Given that,
TSA of sphere = 5(CSA of cone)
4πr² = 5(πrl)
4×5² = 5 ( 4l)
100 = 20 l
l = 5cm
we know, l² = h² + r²
5² = h² + 4²
25 = h² + 16
h = 3cm
therefore, height (h) = 3cm
and,
volume of cone = 1/3πr²h
=> 1/3 × 22/7 × 4² × 3
=> 352/7 cm³
so , volume of cone is 352/7 cm³ or 50.28cm³.
hope it will be helpful...
TSA of sphere = 5(CSA of cone)
4πr² = 5(πrl)
4×5² = 5 ( 4l)
100 = 20 l
l = 5cm
we know, l² = h² + r²
5² = h² + 4²
25 = h² + 16
h = 3cm
therefore, height (h) = 3cm
and,
volume of cone = 1/3πr²h
=> 1/3 × 22/7 × 4² × 3
=> 352/7 cm³
so , volume of cone is 352/7 cm³ or 50.28cm³.
hope it will be helpful...
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