Question

1)The trajectory of a projectile is................(1)
2)With the help of of a vector diagram state parallelogram law. (2)
3)A particle is projected up into air with a speed of 20m/s at an angle of projection 30°. What is themaximum height reached by it?(2)
4)Obtain an expression for centripetalacceleration in
terms angular speed Omega. (3)

Answer 1

Answer of 3)  u²sin²β/2g

                      =20*20*(sin30)²/2*10

                      =(400*1/4)÷20

                       =5