1) The two numbers whose sum is 42 and difference is 16 are and
Answers
Answered by
0
Step-by-step explanation:
let 1st no. is x
and 2nd no. is y
A.T.Q
x+y=42
x=42-y
x-y=16
42-y-y=16
-2y=16-42
-2y=-26
y=14
x=42-14
x=28....
Answered by
2
Answer:
x = 29 and y = 13
Step-by-step explanation:
Let the numbers be x and y.
Given that :
x + y = 42. ...(1)
x - y = 16. ...(2)
Subtracting equation (2) from equation (1),
x + y = 42
- x - y = 16
- + -
2y = 26
2y = 26
y = 26/2
y = 13
From equation (1),
x + y = 42
x + 13 = 42
x = 42 - 13
x = 29
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