Question

1.
The value of k, so that quadratic equation 2x2 + kx + 3 = 0 has two equal roots.
(a) 25 (b) + 2/6 (c) + 2/3 (d) none of these​

Answer 1

Answer:

For equal roots

D=0

b^2-4ac=0

k^2-4*2*3=0

k^2-24=0

k^2=24

k=√24

k=2√6

(b) 2√6 is the correct answer

Hope this helps

thank u

Answer 2

$2 {x}^{2} + kx + 3 = 0$

as the above equation has two equal roots,

HERE D=0,I.e.

$d = {b}^{2} - 4ac$

And here a=2,b=k and c=3

So,

${b}^{2} - 4ac = {k}^{2} - 4 \times 2 \times 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: 0 = {k}^{2} - 24$

so,

${k}^{2} = 24 \\ k = \sqrt{24} \\ k = 2 \sqrt{6} (ans)$

Therefore value of k is 2root6

❣HOPE IT IS HELPFUL ❣