Question

1.The velocity of a moving point changes according to the equation v=(36+21+1) m/s. Find the distance
covered by the point in 10 seconds from the start.
2.A point moves with velocity v=(91-8t) m/s. Find the distance covered by the point during the fourth second from the start.
3.A point moves with velocity v=(6+2 +4) m/s. Find the distance covered by the point during 5 seconds from the beginning of motion​

Answer 1

Answer:

1) 2.9 m

Explanation:

1) S=1/2*(u+v)/t

=1/2*(0+58)/10

=1/2*58/10

=29/10

=2.9 m