Question

1. Three unbiased coins are tossed together. Find
the probability of getting

(iii) atmost 2 heads.​

Answer 1

Answer:

0.5

Step-by-step explanation:

hht

hth

thh

hhh

these 4 are possible

so, 4/8=0.5

Answer 2

Step-by-step explanation:

S={HHH, HHT, HTH, THH, TTH, TTT}

N(S) =6

Let A be the event of getting almost 2 heads

A={HHH, HHT, HTH, THH}

N(A)=4