Question

1. Two coins
coins are tossed simultaneously
find the
probability of getting
at least one head.

​

Answer 1

getting at least 1 head:

E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.

Answer 2

Answer:

1/2 is the probablity of getting head

Step-by-step explanation:

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