Question

Let f be a function defined by f(x) = 4x2

– 8x +10. Find the range of f(-3), f)2), f(1)

and f(0).​

Answer 1

Step-by-step explanation:

Given,

f(x) = 4x² - 8x + 10

Now,

f(-3) = 4(-3)² - 8(-3) + 10

= 4(9) - 8(-3) + 10

= 36 + 24 + 10

= 36 + 34

= 70

:. The range of f(-3) = 70.

Now consider,

f(2) = 4(2)² - 8(2) + 10

= 4(4) - 8(2) + 10

= 16 - 16 + 10

= 0 + 10

= 10

:. The range of f(2) = 10.

Now consider,

f(1) = 4(1)² - 8(1) + 10

= 4(1) - 8(1) + 10

= 4 - 8 + 10

= -4 + 10

= 6

:. The range of f(1) = 6.

Now consider,

f(0) = 4(0)² - 8(0) + 10

= 4(0) - 8(0) + 10

= 0 - 0 + 10

= 10

:. The range of f(0) = 10.