Question

1. Two masses of 6 kg and 4 kg are connected to the
two ends of a light inextensible string that goes
over a frictionless pulley. Find the acceleration of
the masses and the tension in the string when the
masses are released. Take g = 10 ms?. 40=0
[Central Schools 17] (Ans. 2 ms?, 24 N)

Answer 1

Answer:

ANSWER

Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up

So the equation of net force on 6kg is given as

6×10−T=6a

equation of net force on 4kg is given as

T−4×10=4a

now add the above two equations

6×10−(4×10)=(6+4)×a

60  - 40 = 10a

a = 2m/s  

2

 

So 6 kg will accelerate downwards while 4 kg will accelerate upwards  

with acceleration 2 m/s  

2

 

now in order to find the tension force

T−4×10=4×2

T = 48N

So the tension in the string in 48 N

YUP THATS YOUR ANSWER

Explanation: