1) Two numbers are in the ratio 5:3 if they differ by 18. what are the numbers.
2) Three consecutive integers add up-to to 51, What are the integers.
Answers
Solution:
Answer-(1)
Given:
Two numbers are in the ratio 5:3 if they differ by 18.
Find:
What are the numbers.
According to the given question:
• Let us assume the whole quantity by "M".
• The two numbers be "5M" and "3M".
Calculations:
→ 5M - 3M = 18
→ 2M = 18
→ M = 18/2
→ M = 9
The first number is 5M = 5 × 9 = 45
The second number is 3M = 3 × 9 = 27
Therefore, 45 and 27 are the required numbers.
Answer-(2)
Given:
Three consecutive integers add up-to to 51.
Find:
What are the integers.
According to the given question:
• Let us assume the three consecutive integers be "N".
• [N, N, N + 2] = 3 N + 2
Calculations:
→ N + N + 1 + N + 2 = 51
→ 3N + 3 = 51
→ 3N = 51 - 3
→ 3N = 48
→ N = 48/3 = 16
Therefore, the three consecutive are 16, 17, 18.
Similar question:
The sun of three consecutive multipliers of 8 is 888. Find the multiple.
Solution:
Given:
The sun of three consecutive multipliers of 8 is 888.
Find:
Find the multiple.
Calculations:
Let us assume the three consecutive multiple of 8 be "MN" , "MN + 8" , " MN + 16"
According to statement:
→ MN + MN + 8 + MN + 16 = 888
→ 3MN + 24 = 888
→ 3MN = 888 - 24
→ 3MN = 864
→ MN = 464/3
→ MN = 288
→ MN + 8 = 288 + 8
→ 2 ab
→ MN + 10 = 288 + 16
→ 1304
Therefore, 1304 is the answer.
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Answer:
look bud
1)
18 is the difference.
5a - 3a = 18
= 2a = 18
= a = 9
no.s are 45 and 27 and u can see the difference already.
2)
Add up to 51.
Split into 3
17,17,17
17 + 17 = 34
also 16 + 18 = 34
so 17 + 16 + 18 = 51
common intuition is enough.