Question

1
Two rectangles have the same perimeter of 120 cm. The first rectangle has a side of length 40cm. The second rectangle has a side of length 50 e
of the area of the first rectangle to the area of the second rectangle?
2
Note: Your answer must be in the format romleg.2.3).
25​

Answer 1

Answer:

1.6

Step-by-step explanation:

Perimeter=2(length+breadth)

Area=length*breadth

First Rectangle:

120=2(40+breadth)

breadth=20

Area=800

Second Rectangle:

120=2(50+breadth)

breadth=10

Area=500

Ratio=800/500=1.6

Answer 2

Answer:

ratio of area of rectangle 1 to rectangle 2 = $\frac{800}{500}$

                     = $\frac{8}{5}$ = 1.6

Step-by-step explanation:

given, perimeter of both rectangle  = 120 cm

length of rectangle 1 = 40 cm and length of rectangle 2 = 50 cm

perimeter of rectangle = 2× (length+breadth)

area of rectangle = length × breadth

for rectangle 1:

perimeter: 120 = 2 (40+b)

               120 = 80 +2b

               breadth = 20 cm

area = 20× 40 = 800 cm²

for rectangle 2:

perimeter: 120 = 2(50+b)

                   120 = 100 + 2b

                  breadth = 10

area = 50×10 = 500 cm²

ratio of area of rectangle 1 to rectangle 2 = $\frac{800}{500}$

                     = $\frac{8}{5}$ = 1.6