1. Two stones are thrown vertically upwards
with the same velocity of 49m/s. If they are
thrown one after the other with a time lapse
of 3 second, height at which they collide is
1) 58.8 m
2) 111.5 m
3) 117.6 m
4) 122.5 m
Answers
Answered by
0
Answer:
/Two-stones-are-thrown-vertically...
Nov 28, 2018 · Let's say they collide after time t seconds of throwing first stone. So, we have following equation with bold letters being vectors: r1 = ut + 0.5gt^2 r2 = u(t-3) + 0.5g(t-3)^2 Equating these two equations: 3u = 0.5g[(t-3)^2 - t^2] = -0.5g[(2t-3)
Explanation:
Similar questions