Question

1. Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now?

Answer 1

let the present age of salim is " x " and age of his daughter is " y "

2 years ago , age of salim = x - 2

and age of his daughter = y - 2

now , according to question,

x - 2 = 3 ( y - 2 )

x - 2 = 3y - 6

x - 3y = - 4 ---eq(1)

6 years later ,

age of salim = x + 6

and age of his daughter = y + 6

according to question,

( x + 6 ) = 2 ( y + 6 ) + 4

x + 6 = 2y + 12 + 4

x - 2y = 10 ----eq(2)

now , subtract equation (1) from eq(2)

x - 2y = 10

x - 3y = - 4
____________________ , we get

y = 14

put value of y in eq.(2) , we get

x - 2( 14 ) = 10

x - 28 = 10

x = 28+ 10

x = 38

hence, salim x = 38 years old , and his daughter y = 14 years old
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"hope helps"
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Answer 2

Answer:

14 years, 38 years

Step-by-step explanation:

Let the age of daughter two years be x years.

Two years ago:

Age of Salim = 3x

6 years later:

Age of daughter = x + 2 + 6 = x + 8

Age of Salim = 3x + 2 + 6 = 3x + 8.

Given that 6 years later he will be 4 years older than twice her age.

⇒ 3x + 8 = 2(x + 8) + 4

⇒ 3x + 8 = 2x + 16 + 4

⇒ 3x + 8 = 2x + 20

⇒ x = 12

Therefore:

Present age of daughter = x + 2 = 14

Present age of Salim = 3x + 2 = 38

Hope it helps!