Question

1 upon 7 minus 4 root 3 rationalize denominator of each of the following expression​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} = \frac{1}{7 - 4 \sqrt{3} } \\ \\ rationalising \: \: the \: \: denominator..... \\ \\ = \frac{1}{7 - 4 \sqrt{3} } \times \frac{7 + 4 \sqrt{3} }{7 + 4 \sqrt{3} } \\ \\ = \frac{7 + 4 \sqrt{3} }{ {(7)}^{2} - {(4 \sqrt{3} })^{2} } \\ \\ = \frac{7 + 4 \sqrt{3} }{49 - 16 \times 3} \\ \\ = \frac{7 + 4 \sqrt{3} }{49 - 48} \\ \\ = 7 + 4 \sqrt{3} \end{gathered}

=

7−4

3

1

rationalisingthedenominator.....

=

7−4

3

1

×

7+4

3

7+4

3

=

(7)

2

−(4

3

)

2

7+4

3

=

49−16×3

7+4

3

=

49−48

7+4

3

=7+4

3

Answer 2

Answer:

which class of maths is this ?

Step-by-step explanation:

i don't know this answer