1 upon root 2 + root 3 + root 10
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so what we have to find out here....
1/[√10+(√3+√2)] × [√10-(√3+√2)]/[√10-(√3+√2)],
[√10-(√3+√2)]/[(√10)²-(√3+√2)²],
[√10-√3-√2]/[10-3-2-2√6],
[√10-√3-√2]/[5-2√6],
[√10-√3-√2]/(5-2√6) × (5+2√6)/(5+2√6),
[(√10-√3-√2)(5-2√6)]/[(5)²-(2√6)²],
[(√10-√3-√2)(5-2√6)]/[(25-24)],
[(√10-√3-√2)(5-2√6)]/1
1/[√10+(√3+√2)] × [√10-(√3+√2)]/[√10-(√3+√2)],
[√10-(√3+√2)]/[(√10)²-(√3+√2)²],
[√10-√3-√2]/[10-3-2-2√6],
[√10-√3-√2]/[5-2√6],
[√10-√3-√2]/(5-2√6) × (5+2√6)/(5+2√6),
[(√10-√3-√2)(5-2√6)]/[(5)²-(2√6)²],
[(√10-√3-√2)(5-2√6)]/[(25-24)],
[(√10-√3-√2)(5-2√6)]/1
sagar7061:
rationalize
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1(√2+√3+√10)
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