1 upon under root 2 + under root 3
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Answer:
√3-√2
Explanation:
Given 1/(√2+√3)
= (√3-√2)/[(√3+√2)(√3-√2)]
= (√3-√2)/[(√3)²-(√2)²]
[Since. ,(x+y)(x-y)=x²-y² ]
= (√3-√2)/(3-2)
= √3-√2
••••
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Hey !
Refer the below attachment !
Thanks !
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