Question

(1) Use Gauss' law to prove that the electric field inside a uniformly charged spherical shell is zero ​

Answer 1

Explanation:

Telling wait for a few minutes

Answer 2

Gauss' law :

Explanation:

Gauss Law states that the whole electrical flux out of a closed surface is capable of the charge closed divided by the permittivity.

The electrical flux in a locality is outlined because the force field increased by the world of the surface projected during a plane and perpendicular to the sphere.

According to the Gauss law, the whole flux connected with a closed surface is 1/ε0 times the charge closed in by the closed surface.

∴ Eds = $\frac{q}{\epsilon_o}$

where

E = intensity of the electric field

ds = surface area

q = charge on the surface area

ε0 = the electric constant.

But the area of the gaussian surface is the area of the sphere

∴ ds = 4π$r^2$ &

    q = 0

E (  4π$r^2$ ) = $\frac{0}{\epsilon_0}$

E = 0

Hence proved.

Refer to the following attachment: