Question

1. Using appropriate properties find,
a) (-2/3)x(3/5)+(5/2)-(3/5)x(1/6).

Answer 1

(-2/3)x(3/5)+(5/2)-(3/5)x(1/6)

=(-2/5)+(5/2)-(1/10)

=1/2

Answer 2

$\huge\sf{ \underline{ \underline{Question}}}$

• $\sf{(\dfrac{-2}{3})\times\dfrac{3}{5}+(\dfrac{5}{2})-(\dfrac{3}{5})\times(\dfrac{1}{6})}$

$\huge\sf{ \underline{ \underline{Answer}}}$

• $\large\sf{2}$

$\huge\sf{ \underline{ \underline{Concept\:Used}}}$

• $\sf{ \boxed{ \boxed{Bodmas\:Rule}}}$

$\huge\sf{ \underline{ \underline{Solution}}}$

$\sf{ }$

$\mapsto\sf{(\dfrac{-2}{3})\times\dfrac{3}{5}+(\dfrac{5}{2})-(\dfrac{3}{5})\times(\dfrac{1}{6})}$

$\sf{ }$

$\mapsto\sf{\dfrac{-2}{\cancel{3}}\times\dfrac{\cancel{3}}{5}+\dfrac{5}{2}-\dfrac{\cancel{3}}{5}\times\dfrac{1}{\cancel{6}}}$

$\sf{ }$

$\mapsto\sf{\dfrac{-2}{5}+\dfrac{5}{2}-\dfrac{1}{10}}$

$\sf{ }$

$\mapsto\sf{\dfrac{-4+25-1}{10}}$

$\sf{ }$

$\mapsto\sf{\dfrac{20}{10}}$

$\sf{ }$

$\mapsto\sf{ \purple{2}}$

$\sf{ }$

$\huge\sf{ \underline{ \underline{ \red{ So\:Answer\:is\:2}}}}$