Question

1. (v) Find the number of zeroes at the end of the number 2^2 × 5^5 × 7^10000 × 11.

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Answer 1

Heya !!!!


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$= > {2}^{2} \times {5}^{5} \times {7}^{10000} \times 11 \\ \\after \: solving \: we \: get \\ \\ = > 4 \times 3125 \times {7}^{10000} \times 11 \\ \\ = > 137500 \times {7}^{10000} \\ \\ = > 1375 \times {7}^{1000} \times {10}^{2}$


So the number of zeroes at the end of the number is 2.


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