Question

1. विजयकडे 20 किलोग्रॅम ज्वारी व 30 किलोग्रॅम गहू आहेत. सर्व धान्य पिशव्यांमध्ये भरावयाचे आहे. प्रत्येक पिशवीत समान वजनाचे धान्य भरायचे आहे तर जास्तीत जास्ती किती वजनाचे धान्य प्रत्येक पिशवीत भरता येईल?
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Answer 1

Step-by-step explanation:

20 kg jwari

5×4 = 20

30 kg gahu

5×6 = 30

6+4 = 10

10 pishvya bharta yeil

Answer 2

Step-by-step explanation:

Given Vijay has 20 kg of jowar and 30 kg of wheat. All grains are to be packed in bags. If the same weight of grain is to be filled in each bag, what is the maximum weight of grain that can be filled in each bag?

• So quantity of jowar Vijay is having is 20 kg
• So quantity of wheat Vijay is having is 30 kg
• According to the question we have
• In each bag same weight of grain is to be filled, so we need to find the maximum weight of grain that can be filled in each bag.
• So the highest common factor has to be found. So we get
• hcf of 20,30.
• The factors of 20 and 30 are
• 20 = 2 x 2 x 5
• 30 = 2 x 3 x 5
• So the common factor is 2 x 5 = 10 kg
• So a maximum of 10 kg grain can be filled in each bag.

Reference link will be

https://brainly.in/question/28242985