1. (vi) Will the number 6^m × 25^n , where m < n , have zeroes at the end. If yes, how many ?
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Hey!!!
As promised I'm here to help you
Good Evening
_____________
We have
=> 6^m x 25^n
=> (2x3)^m x (5²)^n
We have
=> 2^m x 3^m x 5^2n
Here
We have both
2 and 5
Thus we know any number having both 2 and 5 as their factor end with a zero
=> 2 x 5 = 10
Thus 6^m x 25^n will end with a zero
____________
Hope this helps ✌️
Good Night :-)
As promised I'm here to help you
Good Evening
_____________
We have
=> 6^m x 25^n
=> (2x3)^m x (5²)^n
We have
=> 2^m x 3^m x 5^2n
Here
We have both
2 and 5
Thus we know any number having both 2 and 5 as their factor end with a zero
=> 2 x 5 = 10
Thus 6^m x 25^n will end with a zero
____________
Hope this helps ✌️
Good Night :-)
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