Question

Alima has 76 coins a mix of 50p and 25p find there no. if the total money she has 29

Answer 1

Hey there!
For your question, let's assume there are "x" number of 50 p coins and "y" number of 25 p coins.

Hence,

$x + y = 76$
Thus Total Money =
$0.5x + 0.25y$
Since 50p = Rs 0.5 and 25p = Rs 0.25

But we have been given that the total money Alima has is Rs 29. Hence:

$0.5x + 0.25y = 29 \\ \frac{x}{2} + \frac{y}{4} = 29 \\ \frac{1}{4}(2x + y) = 29 \\2x + y = 116 \\ x + ( x+ y) = 116$
Here we know that (X + Y) is equal to 76, from the above equation, so we substitute it in this equation.

$x + 76 = 116\\ x = 116 - 76 \\ x = 40$
Now we find the value of Y, using the first equation:

$x + y = 76 \\ 40 + y = 76 \\ y = 76 - 40 \\ y = 36$
Hence X = 40 and Y = 36.

Thus Alima has forty 50p coins and thirty-six 25p coins.

Answer 2

Hey mate!

Here's your answer!!
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Let's first clear this, here p is “paise”.

Total money = ₹29

Now, let the number of 50 paise coins be x and the number of 20 paise be (76 - x).

According to the situation,

50x + 25(76 - x) = 2900 paise (₹29)

∴ 50x + 1900 - 25x = 2900

∴ 25x = 2900 - 1900

∴ 25x = 1000

∴ x = 1000/25

∴ x = 40

Therefore, the number of coins of 50 paise is 40 and the the number of coins of 25 paise is (76 - 40) = 36.
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