Question

(1 – w)(1 - w2)(1 – w')(1 - w5) = 9​

Answer 1

Answer:

Step-by-step explanation:

Remember 1+w+w² = 0; w³ = 1

(1 – w)(1 - w²)(1 – w⁴)(1 - w⁵)

= (1 – w)(1 - w²)(1 – w³.w)(1-w³.w²)

= (1 – w)(1 - w²)(1 - w) (1 - w²)

= (1-w)²(1 - w²)²

= (1 - 2w + w²)(1 - 2w² + w⁴)

=  (1 - 2w + w²)(1 - 2w² + w³.w)

= (1 - 2w + w²)(1 - 2w² + w)

= ( - 2w -w)(-2w²-w²)

= (-3w)(-3w²)

= 9w³

= 9.

= R.H.S