Question

1, w, w² are cube roots of unity then the value of
(a+b+c) (a + bw + cw²) (a + bw² + cw) =​

Answer 1

Answer:

Since w being cube root of unity then w

3

=1.

Then,

(c+aw+bw

2

)

(a+bw+cw

2

)

=w

2

w

2

(c+aw+bw

2

)

(a+bw+cw

2

)

=w

2

(a+bw+cw

2

)

(a+bw+cw

2

)

[ Since w

3

=1,w

4

=w.]

=w

2

.