Question

Give output of the following function where x and

y are arguments greater than 0. Show the dry

run/working.

void confusing ( int x, int y )

{

int d=2;

While(d<=x)

{

if (x % d = = 0 )

{

System.out.print( d + “ “ );

x= x / d;

}

else

d = d +1;

}

}

(i) What will the function confusing (24) displaying? (2)

(ii) What will the function confusing (15) displaying? (2)

(iii) In one line, state what the function confusing() is displaying.​

Answer 1

Answer:

lse

d = d +1;

}

}

(i) What will the function confusing (24) displaying? (2)

(ii) What will the function confusing (15) displaying? (2)

(iii) In one line, state what the function confusing() is displaying.

Answer 2

Answer:

Bahut lamba hai mereko itna time nahi hai padhne ka

agli baar padh ke bolna

Tab tak hum iska answer dete hai

2+2=5

PROVED !

HAVE A NICE DAY.....TO ME