Question

(1) What happens when
(a) chlorine gas reacts with cold and dilute solution of NaOH?
(b) XeF2 undergoes hydrolysis ?
(ii) Assign suitable reasons for the following:
(a) SF6 , is inert towards hydrolysis.
(b) H3PO3 is diprotic.
(c) Out of noble gases only Xenon is known to form established chemical
compounds.
(1) Considering the parameters such as bond dissociation enthalpy, electron gain
enthalpy and hydration enthalpy, compare the oxidizing power of F2 and Cl2
(ii) Complete the following reactions :
(a) Cu + HNO3(dilute)
(b) Fe3+ + SO2 +H2O →
(c) XeF4 +02F2 →​

Answer 1

Chlorine gas is oxidized and reduced to OCl and Cl ion .

Cl2+ Dil. NaOH = NaOCl + NaCl +H2O

b. XeF2 undergoes hydrolysis to produce oxygen gas and hydrogen fluoride and xenon .

ii. A . Yes SF6 is inert towards hydrolysis it's inertness is due to sterically protected 6 fluorine atoms

B. H3PO3 is diprotic acid as when it is added to water 2 H^+ realeased.

C. Xenon form chemical compounds because it's inner electrons screen outer electrons from the nucleus.

Answer 2

Answer:

(i) (a) When chlorine gas reacts with cold and dilute solution of NaOH, NaOCl is formed.

(b) XeF2 undergoes hydrolysis

(ii) (a) Sulphur is sterically protected by 6F-atoms and hence does not allow H2O molecules to attack S-atom. Therefore SF6 is inert to hydrolysis.

(b) H3PO3 is diprotic as 2 H-atoms are joined through oxygen atoms and are insoluble whereas the third H-atoms is linked to phosphorous directly and is non-ionisable.

(c) Only Xenon is known to form chemical compounds as it has least ionisation energy among noble gases and hence forms compounds easily.