1. What is the probability that a non-leap year selected at random will have 53 sundays. 2.In a lottery there are 10 prizes and 25 blanks. Find the probability of getting a prize.
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1: Non leap year -365 days
52 weeks -364 days (extra days= 1) n(A) =1
p(A) =n (A)/n (S)
p(A) = 1 /7
2 total (s) = 10+25 = 35
n(p) prizes = 10
p(P) = n(P)/ n(S)
p(P) = 10/ 35
p(P)= 2 /7
hope it helps u
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